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Eduardo Longa's user avatar
Eduardo Longa's user avatar
Eduardo Longa's user avatar
Eduardo Longa
  • Member for 8 years, 10 months
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Minimizing area in relative homology class
I realized that the boundary of a minimizer may be empty, so it is not a free boundary hypersurface.
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Minimizing area in relative homology class
Another question: is the minimizer surface stable as a free boundary minimal surface?
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Minimizing area in relative homology class
Yes, I know that. What I meant was: apply the procedure for the double and obtain a hypersurface $\Sigma’ \subset D(M)$. Now let $\Sigma_0 = \Sigma’ \cap M$. Is $\Sigma_0$ minimal free boundary inside $M$?
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Minimizing area in relative homology class
Will the result surface be free boundary?
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Local isometry implies covering map: nonempty boundary case
Related question: is a local isometry a local diffeomorphism, even in the boundary case? If so, a local isometry must send boundary to boundary.
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Local isometry implies covering map: nonempty boundary case
But in this case $N$ does not have a boundary, which is assumed in my question.
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Why does this PDE have a solution?
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Special Riemannian metric on the product
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Special Riemannian metric on the product
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Special Riemannian metric on the product
@AntonPetrunin what is $k$ and what happens when $t=0$?
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