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Rene Recktenwald's user avatar
Rene Recktenwald's user avatar
Rene Recktenwald's user avatar
Rene Recktenwald
  • Member for 9 years, 1 month
  • Last seen more than 2 years ago
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Why is the flat cotorsion pair actually a cotorsion pair?
Could you be a bit more specific? I know the case of $R$-modules but I am unable to generalize the proof to the case of ringed spaces. One problem is that for sheaves the distinction between internal and external $Hom$ and $Ext$ has to be made.
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When is finding an explicit inverse of an isomorphism not possible
Thank you for the answer. Is it possible to write down explicitely where an element of $H^n(H,CoInd_H^G(A))$ gets mapped to?
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When is finding an explicit inverse of an isomorphism not possible
If one chooses such a splitting, how would you make this choice into an inverse for the Shapiro Lemma?
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Concrete formula for Shapiro's Lemma
@tj_: Could you explain what the inverse is?
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Landweber Exact Functor Theorem for Cohomology
Ups my bad :) So we can get $H^*(X;\mathbb{Q})$ but only for finite CW-Complexes? In particular I don't see any of the theory of chern classes here? This is confusing to me, because I would start with the Chern classes to make $H^*(X;\mathbb{Q})$ into a $MU^*$-module in the first place.
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Landweber Exact Functor Theorem for Cohomology
I am aware that they are coming from spectra, but I am not sure how to translate one into the other. Landweber writes in the original paper that it gives a homology theory on all CW-spectra and Rudyak does the same. So there are versions with non-finite complexes. Also surely one would want to be able to talk about $\mathbb{C} P^\infty$ which is an infinite complex
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If presheaf is zero on a covering is the sheaf zero?
Yes I meant what @Phil said. Treat the system as a system in the category of abelian groups, i.e. think of it as the image of the functor. Then every object maps to zero IN the direct system. Is the last line still wrong?
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If presheaf is zero on a covering is the sheaf zero?
@pro Yes, see the answer I just posted. Please let me know if there is a mistake.
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