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Alex Wenxin Xu's user avatar
Alex Wenxin Xu's user avatar
Alex Wenxin Xu's user avatar
Alex Wenxin Xu
  • Member for 9 years, 1 month
  • Last seen more than 4 years ago
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How bad could $\|A^k\|$ be when $\rho(A) < 1-\delta$
@YemonChoi, Thanks for the comments. Please see my reply to Christian as well. I mainly just wanted to control $\|A^k\|$ in a non-asymptotic way. In other words, I'd like to have some version of non-asymptotic Gelfand's formula.
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How bad could $\|A^k\|$ be when $\rho(A) < 1-\delta$
@ChristianRemling, Thanks for all your comments. I guess it's not clear what I want to prove and that's the beauty of its right? I just wanted to have something to bound about $\|A^k\|$ in terms of $\rho(A)^k$ weakly. For example, if $\rho(A) < 1/2$, can you say $\|A^k\| \le ||A||^{100} (2/3)^k$. I am looking for the correct theorem to be proved here -- so what's the right bound is just my question probably. Thanks!
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How bad could $\|A^k\|$ be when $\rho(A) < 1-\delta$
@IgorRivin Please see my edit of the question and my comments to Sebastian. I would really like to get something constructive here..
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How bad could $\|A^k\|$ be when $\rho(A) < 1-\delta$
@SebastianGoette Thanks! yeah I kind of thought such counter-examples. but this cases have a simple fix -- the frobenius norm of the matrix is bounded. So my point here is not to find a counter example but I'd like to get some constructive theory that really rule out the bad instances.
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