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Safwane's user avatar
Safwane
  • Member for 12 years, 3 months
  • Last seen more than a week ago
  • London, Royaume-Uni
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revised
Continuous self-maps of the plane are semiconjugate or conjugate?
added 69 characters in body
asked
Continuous self-maps of the plane are semiconjugate or conjugate?
comment
Is the infinite product map $(∏_{i=1}^{∞}S_{i})×f$ topologically transitive
@LSpice: No, mixing imply transitive.
comment
Is the infinite product map $(∏_{i=1}^{∞}S_{i})×f$ topologically transitive
@YCor: If you have a conterexample, then we are done
comment
Is the infinite product map $(∏_{i=1}^{∞}S_{i})×f$ topologically transitive
@PiotrHajlasz: But this number is not a prime. My fovirate numbers are primes.
revised
Is the infinite product map $(∏_{i=1}^{∞}S_{i})×f$ topologically transitive
added 49 characters in body
comment
Is the infinite product map $(∏_{i=1}^{∞}S_{i})×f$ topologically transitive
@YCor: Yes. I will add this in the question.
asked
Is the infinite product map $(∏_{i=1}^{∞}S_{i})×f$ topologically transitive
awarded
 Custodian
accepted
Finding a solution for this system of two diophantine equations (depending on a parameter)
revised
Finding a solution for this system of two diophantine equations (depending on a parameter)
modifying the function mod
suggested
Approve
Finding a solution for this system of two diophantine equations (depending on a parameter)
revised
Finding a solution for this system of two diophantine equations (depending on a parameter)
I add $ to each mathematical symbol.
suggested
Approve
Finding a solution for this system of two diophantine equations (depending on a parameter)
comment
Finding a solution for this system of two diophantine equations (depending on a parameter)
@NoahSchweber: It is a result when I try to solve a long fractionaire diophantine equation. I just reduced the problem in this form.
asked
Finding a solution for this system of two diophantine equations (depending on a parameter)
accepted
A problem of divisibility
comment
A problem of divisibility
@ Max Alekseyev: It seems that the property of division does not holds true for all $n$ unless one requires some congruance.
comment
A problem of divisibility
@ Max Alekseyev: But you then get $a_{n}= 2(n+1)(2n+1)^{3} $ and $b_{n }= -(n-1)(n+1)(2n+1)^{3}$ and there is no possibility of division unless $n$ is odd.
revised
A problem of divisibility
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