BS.'s user avatar
BS.'s user avatar
BS.'s user avatar
BS.
  • Member for 13 years, 10 months
  • Last seen more than 2 years ago
44 votes
Accepted

Computational complexity of computing homotopy groups of spheres

31 votes
Accepted

connectivity of the group of orientation-preserving homeomorphisms of the sphere

29 votes

Vanishing of Euler class

26 votes

Examples of non-diffeomorphic smooth manifolds with diffeomorphic tangent bundle

24 votes
Accepted

Conformal embedding of Riemann surfaces into 3-space

23 votes
Accepted

A property of the unit circle

20 votes

Without choice, can every homomorphism from a profinite group to a finite group be continuous?

20 votes

Is the boundary $\partial S$ analogous to a derivative?

19 votes
Accepted

Topologies on the field of rationals

18 votes

Cheap, non-constructive, free group generating rotations for Banach-Tarski

17 votes

Which immersed plane curves bound an immersed disk?

16 votes
Accepted

Is a smooth action of a semi-simple Lie group linearizable near a stationary point?

16 votes
Accepted

Nice orthonormal basis for L^2(Cantor set)

15 votes
Accepted

Group ring computation

15 votes
Accepted

Infinite simple Galois groups

15 votes
Accepted

Fourier transform of a bounded function

14 votes
Accepted

Equivalence between statements of Hodge conjecture

13 votes

Double a manifold with boundary

13 votes
Accepted

Closure of the orbits of the $SL(2,\mathbb{Z})$-action on $\mathbb{R}^2$

13 votes

Is the space of immersions of $S^n$ into $\mathbb R^{n+1}$ simply connected?

13 votes
Accepted

Norm of $n$-linear symmetric forms

11 votes

Are manifolds admitting a circle foliation covered by manifolds with a (non-trivial) circle action?

11 votes

Simultaneous diophantine approximation

11 votes
Accepted

Is the tangent bundle of the long line $L$ homeomorphic to $L\times\mathbb R$?

10 votes

Is there a measure zero set which isn't meagre?

10 votes

Why is the Hahn-Banach theorem so important?

10 votes
Accepted

Can a metric conformal to a Kahler metric be Kahler?

9 votes
Accepted

Kazhdan's property T for Kahler surfaces

9 votes
Accepted

Finite, abelian, yet "fugitive" orthogonal subgroups

9 votes
Accepted

Holomorphic functions in almost-complex geometry