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JeremyKun
  • Member for 14 years, 6 months
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Freiheitssatz implies a finitely generated one relator group embeds in a two-generator one relator group?
I think I need a slight clarification, because I was promised this works for every one relator group, regardless of the relator. I know the Freiheitssatz extends to the case when the relator does not necessarily involve all generators, but the chosen subset still excludes a generator involved in $r$. However I'm not so sure this proof extends in a similar way. Take the case where $r = g_1^k$ involves a single generator, then it seems to me that any HNN extension (at least, the construction used here) would necessarily have at least three generators. Is there something I'm missing here?
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Does the group given by this presentation have an element of order 2?
No. It is definitely an HNN extension of a free group. I just posed the more general question because I didn't know of this theorem on HNN extensions, and thought to answer it from a different angle.
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Does the group given by this presentation have an element of order 2?
This is unfortunate for at least one author who I'll leave anonymous, because it provides a counterexample to a theorem in one of his books on one relator groups.
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Sufficient Conditions for Free Indecomposability
I apologize for the ignorance, but is that a variation/application of Helly's theorem on convex sets? Could you point me to a proof of the sufficient condition above?
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Fundamental groups of closed hyperbolic 3-manifolds are freely indecomposable
This is the proof that was communicated orally to me, but I was looking for the name or to see it in a book somewhere. This is just what I needed. Thanks!
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