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Incnis Mrsi's user avatar
Incnis Mrsi's user avatar
Incnis Mrsi's user avatar
Incnis Mrsi
  • Member for 10 years, 4 months
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Finite set of non-collinear points on plane with every point having ≥ 3 equidistant neighbors?
@Oscar Lanzi: the midpoint of the arc certainly doesn’t lie on any diagonal of the outer pentagon. Two respective isosceles triangles, mirror-symmetric, have angles 54° (marked with P on the drawing) and 63°, whereas all angles between sides and diagonals of a regular pentagon are multiples of 36°. Anyway some positions on the arc are not eligible due to collinearity constrain.
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Finite set of non-collinear points on plane with every point having ≥ 3 equidistant neighbors?
For c = ±1 al least two given points coincide and, moreover, there is a Re = const line (namely, Re = −1 for c = 1 and Re = 0 for c = −1) having three distinct points on it. The same for powers-of-ξ multiples. Why didn’t the author exclude bad values of c explicitly?
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In the quaternions, "any imaginary unit may be called i"
Just a quibble: $u\bar v + v\bar u$ is an inner product on ℍ, namely the standard inner product by the factor of 2.
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Demystifying complex numbers
The use of MathJax is not mandatory, but if you use it, then at least don’t break things which are fine in plain text
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Demystifying complex numbers
Clifford algebra is a way more arcane than complex numbers. The fact that ℂ is a division algebra (while extensions of ℝ using square roots of positive numbers are not) explains why the minus sign in Clifford multiplication is preferable, but a Clifford algebra hasn’t necessary to be a division algebra, at the end. Ī̲ wouldn’t deem explaining simpler things via complicated things practical.
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Demystifying complex numbers
The same as for mathoverflow.net/a/30185/56921 — vector calculus is not complex calculus! Complex numbers certainly are a good example of an inner product space, and to teach vectors you can use the example of ℂ, but complex multiplication and (especially) division go beyond the vector-based intuition.
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Demystifying complex numbers
This is a conceptual mess. Basic probability theory absolutely doesn’t need complex numbers but—applied to the real world—it is a simplification just like any other theory, QM included. Surely we can (and do) reduce complex amplitudes to dumb probability measures using |·|², but it has nothing to do with “correct description of probability theory”. It is indeed about real-world randomness which extends far beyond Kolmogorov-style probability. Can anybody rewrite, please?
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Demystifying complex numbers
There is some hype about alleged physical relevance of p-adic numbers (in fact, Ī̲ know in person several researchers who built their career upon it), but—as for $\mathbb{Q}_p$—these are either overreaching generalizations or barren conjectures, whereas complex numbers are justified by quantum mechanics alone.
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Demystifying complex numbers
How does the vector calculus identity explain complex numbers? It is about an inner product space, true in every dimension (and not necessary for a positive-definite scalar product). There is dot product in every $\mathbb{R}^n, n\ge 1$, but only for $n = 1, 2, 4$ multiplication exists (and only for $n = 1, 2$ is it commutative). Downvote.
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Demystifying complex numbers
How is Dirac theory based on (parabolic) Schrödinger equation? We know that a solution to Dirac equation is a solution to Klein–Gordon equation which is hyperbolic.
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Demystifying complex numbers
Ī̲ wouldn’t say it demystifies anything.
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Moving general fibers of a fibration
To be pedantic: the empty subset is open everywhere. If you mean “on all fibers of $π$ over $U$”, then wouldn’t it be vacuously true for empty $U$?
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A boundary behaviour of holomorphic functions
Respect for the adjective “non-constant” (although in the full generality it should be stated more cautiously: not locally constant anywhere).
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To describe an invariant trivector in dimension 8 geometrically
Wouldn’t be helpful to observe that both $R_2$ and $R_4$ are not faithful in the same manner? Ī̲ mean that −1 lies in their kernel, hence both, in fact, represent PSL(2)—for k = ℂ known in physics as the special orthochronous Lorentz group—and all spaces mentioned here are endowed with a PSL(2) representation, not merely SL(2).
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Measure in $\mathbb {C} ^p$
oops, it is metric, not volume form
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Measure in $\mathbb {C} ^p$
Oops, Ī̲ missed that $X$ is not (necessarily) one-dimensional.
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