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user90533
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Show that the function $(n+2)\zeta(n+3)-\zeta(n+2)-n-1$ is positive on $\mathbb{N}.$
Is this sum $\sum_{k=2}^{\infty}\left(\frac{n+2}{k^{n+3}}-\frac{1}{k^{n+2}}\right) $ positive for $n\in \mathbb{N}?$
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Closed form formula
Expression for $\frac{1}{(k+m)^n}$: $$ \frac{1}{(k+m)^n} = \frac{1}{m^n} \left( \frac{(m)_k \times (m)_k \times \cdots \times (m)_k}{(m+1)_k \times (m+1)_k \times \cdots \times (m+1)_k} \right), $$ where the products $(m)_k$ and $(m+1)_k$ are repeated $n$ times in the numerator and the denominator, respectively. Series Representation in Terms of Hypergeometric Function: $$ \sum_{k=0}^{\infty} \frac{(m)_k^{n+1} \, (-1)^k}{(m+1)_k^n \, k!} = \frac{\Gamma(n)}{m^n}{}_{n+1}F_{n}\left(m, m, \ldots, m; m+1, m+1, \ldots, m+1; -1\right). $$
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