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@DimaPasechnik what do you mean by "expressible"? $\mathbb{R}$ is not computable, meaning an implementation requires approximation but the algorithm still is correct.
Confusion between hypergeometric/rational "function" and "term". In most litriture, this would classify as a hypergeometric/rational term (even though it is a function, while a hypergeometric function is a "function [...] represented by the hypergeometric series" (wikipedia Hypergeometric Function).
