User user5023

10 Actions

awarded

Nice Question

Oct 16, 2012 at 7:50

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Supporter

Apr 2, 2010 at 16:05

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Scholar

Apr 1, 2010 at 21:50

comment

D'oh. Of course. And thanks for answering the second half as well.

Apr 1, 2010 at 21:38

accepted

Apr 1, 2010 at 21:36

comment

I'm sure there is a simple reason why $|C_H(g)| \geq \frac{1}{k}|C(g)|$ but I'm missing it at the moment.

Apr 1, 2010 at 20:38

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Student

Apr 1, 2010 at 18:05

asked

Apr 1, 2010 at 17:53

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awarded

Teacher

Mar 30, 2010 at 17:35

answered

Mar 30, 2010 at 16:09

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