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zarathustra
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Calculi of pseudodifferential operators and K-theory
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 Informed
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Relations between two Schwartz kernels in dimensions $n$ and $n+1$
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Relations between two Schwartz kernels in dimensions $n$ and $n+1$
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Relations between two Schwartz kernels in dimensions $n$ and $n+1$
@MateuszKwaśnicki Alright I’ll try to work on that, thanks again :)
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Relations between two Schwartz kernels in dimensions $n$ and $n+1$
@MateuszKwaśnicki Thank you very much. Yes I guess we cannot square the last line but I do not really see why. However, from there, would it exist a way to reach $P_0^{-1}(x,x’)$?
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 Yearling
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Relations between two Schwartz kernels in dimensions $n$ and $n+1$
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Relations between two Schwartz kernels in dimensions $n$ and $n+1$
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Relations between two Schwartz kernels in dimensions $n$ and $n+1$
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Relations between two Schwartz kernels in dimensions $n$ and $n+1$
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Relations between two Schwartz kernels in dimensions $n$ and $n+1$
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Relations between two Schwartz kernels in dimensions $n$ and $n+1$
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Relations between two Schwartz kernels in dimensions $n$ and $n+1$
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Relations between two Schwartz kernels in dimensions $n$ and $n+1$
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Relations between two Schwartz kernels in dimensions $n$ and $n+1$
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Relations between two Schwartz kernels in dimensions $n$ and $n+1$
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Milnor’s smoothed corners technique for a product of manifolds with boundary and boundary defining functions
@PierrePC Thanks for your answer! Yes I think you’re right, actually my main problem is when i compute the coefficients of a metric on $\overline{N}$ in which i find this $\frac{1}{\sqrt{\rho_1^2 + \rho_2^2 }}$ (that makes it not smooth). And yes that is probably it, but you mean $f_3 = 2\rho_1\rho_2$ and $f_4 = \rho_1^2 - \rho_2^2$ right? Don’t we have then $\rho = \frac{f_3}{(f_3^2 + f_4^2 )^{\frac{1}{4}}}$? Anyway at the end it’s not smooth :)
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Milnor’s smoothed corners technique for a product of manifolds with boundary and boundary defining functions
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Milnor’s smoothed corners technique for a product of manifolds with boundary and boundary defining functions
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