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Raj Pratap Singh's user avatar
Raj Pratap Singh's user avatar
Raj Pratap Singh's user avatar
Raj Pratap Singh
  • Member for 2 years, 7 months
  • Last seen more than a month ago
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accepted
On Giuga numbers
awarded
 Supporter
comment
On Giuga numbers
@YCor sorry I didn't knew what rollback I thought it will apply the change but it didn't happen
awarded
 Cleanup
revised
On Giuga numbers
rolled back to a previous revision
asked
On Giuga numbers
awarded
 Scholar
accepted
If $p_1$ and $p_2$ are prime numbers, then either $p_1$ divides $\sum_{i=1}^{p_1-1} i^{p_1p_2-1}$ or $p_2$ divides $\sum_{i=1}^{p_2-1} i^{p_1p_2-1}$?
comment
If $p_1$ and $p_2$ are prime numbers, then either $p_1$ divides $\sum_{i=1}^{p_1-1} i^{p_1p_2-1}$ or $p_2$ divides $\sum_{i=1}^{p_2-1} i^{p_1p_2-1}$?
@above thanks for your effort. It's very much appreciated.
awarded
 Student
awarded
 Custodian
reviewed
Approve
If $p_1$ and $p_2$ are prime numbers, then either $p_1$ divides $\sum_{i=1}^{p_1-1} i^{p_1p_2-1}$ or $p_2$ divides $\sum_{i=1}^{p_2-1} i^{p_1p_2-1}$?
revised
If $p_1$ and $p_2$ are prime numbers, then either $p_1$ divides $\sum_{i=1}^{p_1-1} i^{p_1p_2-1}$ or $p_2$ divides $\sum_{i=1}^{p_2-1} i^{p_1p_2-1}$?
edited title
comment
If $p_1$ and $p_2$ are prime numbers, then either $p_1$ divides $\sum_{i=1}^{p_1-1} i^{p_1p_2-1}$ or $p_2$ divides $\sum_{i=1}^{p_2-1} i^{p_1p_2-1}$?
@GH from MO yeah, I corrected it.
awarded
 Editor
revised
If $p_1$ and $p_2$ are prime numbers, then either $p_1$ divides $\sum_{i=1}^{p_1-1} i^{p_1p_2-1}$ or $p_2$ divides $\sum_{i=1}^{p_2-1} i^{p_1p_2-1}$?
edited title
asked
If $p_1$ and $p_2$ are prime numbers, then either $p_1$ divides $\sum_{i=1}^{p_1-1} i^{p_1p_2-1}$ or $p_2$ divides $\sum_{i=1}^{p_2-1} i^{p_1p_2-1}$?
awarded
 Informed