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Anonymous
  • Member for 11 years, 2 months
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Isomorphism type of mapping class group
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Mapping class groups of a punctured surface vs. surface with boundary
I see the problem now, thank you very much!
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Mapping class groups of a punctured surface vs. surface with boundary
I am sorry, but there a still a couple of things I still don't get. I'll write here, there may be naive mistakes, please correct me if I am wrong. $PMCG(S_g^b)$ is generated by Dehn twists around non-trivial simple closed curves, right? Every non-trivial simple closed of $S_g^b$ can be seen as a non-trivial simple closed curve in $S_{g,b}$, so it seems that $PMCG(S_g^b)$ is "naturally" a subgroup of $PMCG(S_{g,b})$. So why does the inclusion $PMCG(S_{g}^b) \to PMCG(S_{g,b})$ not split the sequence above? Thank you in advance.
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Mapping class groups of a punctured surface vs. surface with boundary
Thank you for your answer. Could you clarify your point about abelianizations and precise why the abelianization of $PMCG(S_{g,b})$ is trivial?
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Hamiltonian circuit
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Hamiltonian circuit
You're right. No multiple edges between two points in the interior of the disk. I'll edit.
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Hamiltonian circuit
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Hamiltonian circuit
I know that paper, it's about triangulations of a polygon. Labelled points are inside the disk in my case. Methods used are pure hyperbolic geometry (!)
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