Skip to main content
David S. Newman's user avatar
David S. Newman's user avatar
David S. Newman's user avatar
David S. Newman
  • Member for 11 years, 3 months
  • Last seen more than 3 years ago
revised
Some continued fractions for transcendental numbers
Several people commented that I should write the formulas explicitly, but I have trouble using the format here so I've used Mathematica. Perhaps someone more skillfull could typeset this.
Loading…
comment
Some continued fractions for transcendental numbers
@Douglas Zare I'm going to add the formulas as you've suggested using the format of the programming language Mathematica since I can, hopefully, just copy and paste that. Hopefully someone will typeset them.
comment
A Product Related to Unrestricted Partitions
Can the first factor of the product be (1-x-x^2-x^3-...) that is can all the coefficients be minus one and still satisfy the conditions for the series, that its coefficients be from {-1,0,+1}?
Loading…
awarded
comment
What are the values of this sequence?
My guess about a(F_n-1) being odd was true for the first 21 values of n, but not true for larger values.
revised
What are the values of this sequence?
I changed a(F_n) to read a(F_n-1) to correct some confusion about the coefficient of the constant term
Loading…
awarded
awarded
revised
What are the values of this sequence?
Added missing parentheses
Loading…
reviewed
Approve
asked
Loading…
revised
Is the set of numbers $\{ [n^{3/2}] \mid n\text{ an integer}\}$ a basis of order 3?
I changed the word smallest to largest. I hope I got it right this time.
Loading…
Loading…
comment
What is the density of the reciprocal of the set of cubes?
It seems that the even numbers in the sequence mentioned are numbers which can be written in an odd number of ways as a sum 2a^3+4b^3, where a and b are non-negative numbers.
comment
What is the density of the reciprocal of the set of cubes?
@VladimirDotsenko I think the person to ask is Paul Monsky.
awarded
awarded
comment
What is the density of the reciprocal of the set of cubes?
@dotsenko: I believe that 1/64 is what Kevin O'Bryant told me in a conversation last week, but I could be misremembering.
Loading…
1
3 4
5
6 7