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SashaKolpakov
  • Member for 11 years, 3 months
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Vertices of a Polytope
@PawanAurora: above, Little Addition is linked to your example, and Little Addition 2 is linked to Guenter Rote's answer.
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Vertices of a Polytope
@GuenterRote: in dimension three you may wish to consider fullerenes (liga.ens.fr/~deza/Sem-FullCCirmVirusSpFull/FFullereneConf.p‌​df) as an example of polytopes with many vertices of degree 3 sufficiently far from each other. I think it works, when you cut a number of vertices of a fullerene by triangles, since fullerenes have 5- and 6-gonal faces only. The number of vertices of a fullerene is generally unbounded.
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Vertices of a Polytope
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Vertices of a Polytope
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Vertices of a Polytope
@PawanAurora: I edited my (partially wrong) answer. I will see if I can say anything more now, when you clarified the situation with that nice example.
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Vertices of a Polytope
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Vertices of a Polytope
Thank you! Now I see where I was wrong about the case when you consider facet defining hyperplanes instead of faces: F_P definitely has a new hyperplane, but when it intersects those already in F_Q, it may happen that no new vertices appear (thus, the new hyperplane has to go through some "old" vertices and may chop off some other "old" vertices.
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Closed hyperbolic manifold with right-angled fundamental domain
There are no compact right-angled polytopes in dimensions >= 5 according to Potyagailo and Vinberg. Thus, you cannot expect closed manifolds with right-angled fundamental domains (which [domains] are necessarily compact) in dimensions >= 5. However, you still may construct manifolds with cusp out of right-angled polytopes, which are known to exist up to dimension 8 (Potyagailo and Vinberg, again). The upper bound for their dimension is <=12, however, there are no examples in dimension 9 to 12.
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algorithm to compute the integral orthogonal group
@few_reps: I would be happy to see your paper on arXiv soon. Reading it will be a very interesting continuation of what we discussed before. I'm interested if your method can generate Coxeter or rational-of-pi angled polytopes in dimension four.
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How to examine the convexity of a complex function numerically?
@behradmahboobi: a convex function defined over an open domain, I believe, is always continuous and a.e. differentiable. Thus, the mentioned properties will not contribute anything new to the problem.
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