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Basics
  • Member for 11 years, 4 months
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Cohomologies of double covers
Thanks for the anwer. I am interested in unramified cases.
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Cohomologies of double covers
Thanks for your quick answer but is it still true when the coeffiecient ring is $\mathbb Z$, not $\mathbb R$?
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Why is a Kummer surface simply-connected?
Although one can show that $h^{1,0}=0$, the fundamental group may still have a torsion part. Am I correct?
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Why is a Kummer surface simply-connected?
That's right. But I would like to see more direct proof.
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Why is a Kummer surface simply-connected?
Yes, the quotient is sinulgar. I am wondering why the quotient (or its crepant resolution) is simply-connected.
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