Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.
Artin gluing works without change but the ugly sheaf of rings $i^{-1} \mathcal{O}_X$ appears. The structure sheaf of the formal completion can be understood as an approximation to this sheaf (which however does the job only for coherent sheaves). According to Fujiwara-Kato, one can build an analog with henselizations or Zariski localization taking the role of formal completions, but I haven't worked with those.
P.S. This works only for quasi-coherent sheaves. For example, the module $\mathbb{Q}_p/\mathbb{Z}_p$ becomes zero after tensoring by $\mathbb{Q}_{p}$ and has zero completion.
A good analog is to consider the formal completion (so $\mathbb{Z}_p$ instead of $\mathbb{F}_p$ in your example). See Artin "Algebraization of Formal Moduli: II. Existence of Modifications", Theorem 2.6 for the noetherian affine case, Beauville–Laszlo for the non-affine case with vector bundles, and Ben Bassat–Temkin for a global case.
Fiber length should be lower semicontinuous for flat quasi-finite maps. To see this, you can reduce to the case of base being a dvr, and apply Zariski's main theorem to compactify the map to a finite flat map.
Yes (with a single blowup) if the log resolution is projective (and $X$ is quasi-projective), by II 7.17 in Hartshorne. No in general, for e.g. Hironaka's example (Appendix in Hartshorne) is a proper birational map to $\mathbf{P}^3$ with smooth non-projective source, which can't be a blowup or a sequence of such.
No! Consider the point $1/p$ on the affine line. Yes if $X$ is proper, by the valuative criterion. In a way, $p$-adic completion removes all points for which the valuative criterion fails.
Perhaps you already know this: By Bittner's theorem, $K_0({\rm Var}_K$ is isomorphic to the ring generated by smooth projective varieties modulo relations $[X] - [Z] = [{\rm Bl}_Z(X)] - [E]$ where $Z\subseteq X$ is a smooth closed subvariety and $E\subseteq {\rm Bl}_Z(X)$ is its preimage in the blowup. It follows that every motivic measure on smooth projective varieties (satisfying the blowup relation) extends uniquely to a motivic measure on all varieties, satisfying the scissor relations. So in particular the Hodge polynomial extends uniquely, giving the virtual Hodge polynomial.
I think for perfect complexes we get the pull-back category. For coherent sheaves things might be more complicated since the pull-back functors might not even be defined on the bounded category (because of unbounded Tor).
What I'm saying is that this enriched variant takes values in the category ${\rm FGL}_+(\mathbf{Q}) := \varinjlim_N {\rm FGL}(\mathbf{Z}[1/N])$ rather than ${\rm FGL}(\mathbf{Q})$. The natural functor ${\rm FGL}_+(\mathbf{Q})\to {\rm FGL}(\mathbf{Q})$ is not an equivalence, precisely because the logarithm/exponential series have too many primes in denominators. (A similar construction should work over any field of char. 0, with colimit taken over all f.g. $\mathbf{Z}$-subalgebras.)
(cont.) ...of $E$ (point counts over all finite fields with large enough characteristic) and hence (by Chebotarev density and Tate conjecture) should be able to determine the curve $E$ up to isogeny.
It is true that the formal group over a field of characteristic zero is a very lossy invariant. However, things are maybe not so bad over a number field (say $K=\mathbf{Q}$). Spread out your elliptic curve to a group scheme over $\mathbf{Z}[1/N]$ for some $N$ and take the associated formal group over $\mathbf{Z}[1/N]$. This should actually be an invariant of $E$, the "formal group up to change of coordinates which has finitely many primes in denominators". And as far as I know (somebody here will be able to give references) by work of Honda (?) this formal group remembers the $L$-series ...