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Bobby Grizzard's user avatar
Bobby Grizzard's user avatar
Bobby Grizzard's user avatar
Bobby Grizzard
  • Member for 12 years, 2 months
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Order of torsion group
@WillSawin thanks for keeping me on my toes ;).
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Order of torsion group
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Order of torsion group
Nice! I did state in my "answer" that I assumed the curve was defined over $\mathbb{Q}$, and in fact as you'll see from my comment on the accepted answer, I assumed (based on the fact that that answer was accepted) that OP had intended that. If OP wanted to know what torsion could be defined over $\mathbb{Q}^{(2)}$ for an elliptic curve which is just know to be defined over that field, I don't think we know the answer, although your argument apparently shows the group is still finite in this case.
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Order of torsion group
@Suman First of all, I assume since you accepted this answer that you meant in your original question that the elliptic curves should be defined over $\mathbb{Q}$, and you want to know about $E(K)_tors$ for such curves, where $K$ is the compositum of all quadratic fields. The fact that the curves are defined over $\mathbb{Q}$ is of course crucial in the Fujita & Laska-Lorenz results mentioned above. Secondly, I have an easy way to see that the order of the group is finite. It's maybe too long for a comment here, so see my "answer" below.
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An inverse problem: Number fields attached to elliptic curves over Q
I see -- you mean isomorphic as Galois modules.
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An inverse problem: Number fields attached to elliptic curves over Q
@JSE You mean $\mathbb{Q}(E[p])$ isomorphic to $\mathbb{Q}(F[p])$ implies $E$ and $F$ are isogenous, right? Do you have a good reference for this conjecture?
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Factoring a polynomial in a specific manner
I am guessing it should say "...degree less than $D-l$," not "...$D-d'$."
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What are the strongest conjectured uniform versions of Serre's Open Image Theorem?
Thank you very much for bringing this argument fact (re Conjecture 2'') to my attention! I guess this is the reason for the focus in recent literature on conjectures 1, 1', etc. In your opinion, is there a good reason not to believe in Conjecture 1''? It would be nice if one could say all bounds in the OIT only depend on $[K:\mathbb{Q}]$.
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Action of semidirect products of cyclic groups
I think the most natural action of the group you say is permutations of a set with $p$ elements (it's the "affine general linear group" AGL(1,$p$)). This action is easy to understand. So the group could permute $p$ of the variables in a nice way...
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