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Ali Taghavi's user avatar
Ali Taghavi's user avatar
Ali Taghavi's user avatar
Ali Taghavi
  • Member for 11 years, 5 months
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Topological spaces in which countable intersections of dense open sets have dense interior
Motivation: Let two algebra $A,C$ satisfy the property P and we have a short exact sequence $0\to A\to B\to C\to 0$ does it implies that B satisfies P too?
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Topological spaces in which countable intersections of dense open sets have dense interior
@Gro-Tsen let X be a topological space $X=G \sqcup F$ $G$ open $F$ closed such that both $G, F$ satisfy super Baire. Does this imply that $X$ is a super Baire
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Topological spaces in which countable intersections of dense open sets have dense interior
@DavidGao One another points with classical formulation but motivation from extension theory in algebra:
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Topological spaces in which countable intersections of dense open sets have dense interior
@DavidGao So contrary to your opinion I think the commutative Banach algebraic setting is interesting
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Topological spaces in which countable intersections of dense open sets have dense interior
@DavidGao from the view of dimension theory one may think of possible low dimensional examples of Banach algebra with desired property. I mean dimension in terms of tsr and real rank(M. Riefell's work)
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Topological spaces in which countable intersections of dense open sets have dense interior
@Gro-Tsen What can be said about the topological dimension of spaces you examined(The space with super Baire property)?Are there plenty of low dimensional cases?
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Topological spaces in which countable intersections of dense open sets have dense interior
. So a possible remedy is consideration of commutative Banach algebras
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Topological spaces in which countable intersections of dense open sets have dense interior
@DavidGao Regarding commutative Banach algebra I would suggest the following point: let A and B be two Banach algebras with super Baire property(In terms of essential ideal intersection). Is it true to say that every kind of tensor product $A\otimes B$ is a super baire algebra? This is inspired by that fact that the product of two compact baire space is again a baire space. On the other hand we pose this question in commutative C^* algebras we have an obvious "Yes" but if we drope the commutativity we have diffoculty with two sided ideals...
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Topological spaces in which countable intersections of dense open sets have dense interior
@DavidGao One may keep commutativity but drop the involution $*$ . That is "Banach algebras"
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Topological spaces in which countable intersections of dense open sets have dense interior
@DavidGao Since a manifold do not satisfy the super Baire property so it would be interesting to examin an appropriate NC analogy of the super Baire in an spectral triple
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Topological spaces in which countable intersections of dense open sets have dense interior
@Gro-Tsen May I ask you to add some tags as NCG or operator algebras or functional analysis. This is apparently unrealated to your question but in reality it is related to the subject
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Topological spaces in which countable intersections of dense open sets have dense interior
@YemonChoi "All you have done is a reformulated..." Ok his question is :"Is there a name for this property? So Yemon what is the job of a dictionary translating a name or a word into another language. So I do not see why is not a relevant answer to (the first edition of ) the OP question. Moreover after that I post the answer I found some papers who concern if an intersection of essential ideals is an essential ideal or not. (In case of rings)
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Topological spaces in which countable intersections of dense open sets have dense interior
@Gro-Tsen I do not know if it is apeared somewhere or not? But many years ago i was thinking to NC analogy of Baire property but i disappointed since every compact Hausdorf space is already a Baire space . After you posed your question I reallized that the NC analogy is that a countable intersection of Essential ideals must be an essential ideal. Note that in C[0,1] a countable intersection of essential ideals can be the trivial ideal. Obviously [0,1] does not satisfies your property
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