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Jeff Strom's user avatar
Jeff Strom's user avatar
Jeff Strom's user avatar
Jeff Strom
  • Member for 14 years, 10 months
  • Last seen more than a month ago
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Can one determine the dimension of a manifold given its 1-skeleton?
Interesting starting point: can $S^n$ and $S^m$ be triangluated with isomorphic $1$-skeleta?
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Ways to prove the fundamental theorem of algebra
@AliTaghavi Because $\mathbb{H}$ is not commutative, you can't always collect all the terms of the form $a_0q a_1 q a_2\cdots a_{n-1}q a_n$ (with $a\in \mathbb{H}$) into a single term of the form $a q^n$.
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Proof synopsis collection
Maybe: If $f$ had no fixed point, then $S^{n-1}$ would be a retract of $D^n$. But $D^n$ is contractible and $S^{n-1}$ is not.
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Fiber homotopy equivalence
There may be a tacit “convenient category” hypothesis here; May’s book is freely available online.
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