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I have found a set of 200 pairwise disjoint spreads in McL. So $s_5(McL) \geq 200$. There might be a full resolution but I stopped my search at 200 as it seemed like it was taking too long. I can send you the SAGE code for this if you want. I used a rather brute force way of doing it using the inbuilt implementation of dancing links algorithm in SAGE.
@FelixGoldberg: It seems quite interesting to me. Have you tried to compute the five different spreads they mention in the paper? If you want then you can send more details about what you are working on and trying to achieve via email, [email protected].
Thanks for correcting me. It should be that the number of classes of central involutions is at most the number of involutions in the center of a Sylow 2-subgroup. Since given a central involution f, if H is a Sylow 2-subgroup contained in the normalizer of f then f must itself belong to H as otherwise, H and f would generate a subgroup of order 2|H|.