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anonymous
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probability calculation
Why did you ignore the part $\sum_{k=\lfloor (e-1)/2\rfloor}^{\min(b,e)}\frac{{e \choose k}{me-e \choose b-k}}{{me \choose b}}$?
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probability calculation
Why "the case $r\le 1/2$ is not interesting"?
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probability calculation
The problem actually comes out of some research (but not mathematical research). I have abstracted irrelevant details away from it. What is the definition of "research" here?
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