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mike
  • Member for 11 years, 7 months
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Why is so much work done on numerical verification of the Riemann Hypothesis?
2:The error term in Riemann–von Mangoldt formula (in wikipedia.org) is larger than 1. $\left|N(T)-\left(\frac{T}{2\pi}\log\frac{T}{2\pi e}-\frac{7}{8}\right)\right|<0.137\log T+0.443\log\log T+4.350,\text{ for } T>2.$. How do we use $N(T)$ from this formula to compare the number of numerical zeros from 1:?
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Obstruction to Navier-Stokes blowup with cylindrical symmetry
@JeanDuchon: Could you please provide more info about the reference by D. Serre in Compte Rendus 1999? Thanks a lot-
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Obstruction to Navier-Stokes blowup with cylindrical symmetry
@DenisSerre: Could you list explicitly the reference papers that you mentioned above for Navier-Stokes equations and for Euler equations ? Thanks a lot!
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The Riemann hypothesis as a problem in analysis
@AlexGavrilov: You may wish to look at this recent preprint (arxiv.org/abs/1706.08868). It concerns the zeros of the entire functions as Fourier transforms. The basic complex analysis method used there is based on the approach of Polya and Hurwitz. It is purely analytic because primes do not appear in the preprint.
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The sign of an interesting sum involving a Dirichlet character
@DavidLoeffler: Thanks a lot for the comment. I am sorry that I have not done enough testing.
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The sign of an interesting sum involving a Dirichlet character
Thanks a lot for the detailed answer! I noticed that you used $\chi(k)=-\chi(17-k)$. What is this (anti)symmetry? Best
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The sign of an interesting sum involving a Dirichlet character
Sure. Yes. $Q(\mathrm{Re}\chi_q)=\mathrm{Re}(Q(\chi_q))$.
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The sign of an interesting sum involving a Dirichlet character
changed Dirichlet polynomial to a sum involving Dirichlet character
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