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Anweshi
  • Member for 14 years, 11 months
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Are all Hawaiian Earrings homeomorphic?
Yes that is true. Both the question and the answers given are well within general topology. But the only issue is that general topologists don't worry about this space.
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Are all Hawaiian Earrings homeomorphic?
What counterexample in general topology did you use the Hawaiian ear ring for? I would like to know.
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How to see meromorphicity of a function locally?
IS the monodromy theorem relevant for you?
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Intuition for Group Cohomology
What is the difference between BG and the Eilenberg-Maclane space K(G,1) mentioned in Allen Hatcher's book?
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Why no abelian varieties over Z?
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Why no abelian varieties over Z?
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Why no abelian varieties over Z?
@Ilya. I took a look at page 16. That is Chapter 2 on Faltings theorem, and I had imagined that it was a separate article. Read on, you will find that Faltings settled that too. The role of Shafarevich is that he proved it for elliptic curves -- the proof is rather easy, it can be found in Silverman's book on elliptic curves. The higher dimensional case was then called "Shafarevich conjecture".
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Why no abelian varieties over Z?
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Why no abelian varieties over Z?
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Are all Hawaiian Earrings homeomorphic?
This is a comment about the tag. Nobody studies Hawaiian earring in general topology. The first encounter is when you study algebraic topology -- more precisely, the fundamental group.
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Why no abelian varieties over Z?
Faltings proved that also, along with the Mordell conjecture. See Darmon's article on Faltings' theorem.
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Example of continuous function that is analytic on the interior but cannot be analytically continued?
Why isn't the following used: $g(z)$ has the unit circle as natural boundary, because its derivative $f(z)$ blows up at all roots of unity and has the unit circle as the natural boundary.
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Are all Hawaiian Earrings homeomorphic?
@Mariano. Supposing a_n goes to infinity. Then we should get the wedge. If a_n goes to zero, then it should be the Hawaiian. No?
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Are all Hawaiian Earrings homeomorphic?
Oops, I screwed by deleting my comment and re-posting in a different form.. The one of mine above, should have been the first. Sorry.
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Are all Hawaiian Earrings homeomorphic?
That is the wedge of infinitely many circles. Isn't that non-homeomorphic to the Hawaiian?
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Example of continuous function that is analytic on the interior but cannot be analytically continued?
You could have replaced $n!$ by $n^n$ for instance, and then called it your own!
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Example of continuous function that is analytic on the interior but cannot be analytically continued?
Your clarification(both here and in my deleted answer) had been most helpful. Thanks.
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