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Stefan Kohl's user avatar
Stefan Kohl
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revised
Does negative trichotomy hold for constructive ordinals?
Removed the last paragraph in response to a flag.
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Can a group generated by its involutions, the product of every two of which has order a power of 2, have an element of odd order?
@MaxHorn No, it is not. For example, $(1,2)$ and $(2,3)$ are involutions in ${\rm S}_6$, but their product has order 3 (i.e. not a power of 2).
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Can a group generated by its involutions, the product of every two of which has order a power of 2, have an element of odd order?
@YCor The answer to the easier version of the question you suggested is yes. For example, the four involutions $(1,2)$, $(3,5)$, $(4,6)$ and $(1,3)(2,4)(5,6)$ generate ${\rm S}_6$, and the product of every two of them has order a power of 2.
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Can a group generated by its involutions, the product of every two of which has order a power of 2, have an element of odd order?
@YCor Even for finite groups, I don't know the answer (otherwise I would have written it as a remark to the question).
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near ergodic theory question
appended answer 447721 as supplemental
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Schröder and graphical logic?
rolled back to a previous revision
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An inequality related to Catalan's constant and $\zeta(3)$
appended answer 447618 as supplemental
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Is there an algorithm to generate non-isomorphic Halin graphs?
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