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Hannes Thiel's user avatar
Hannes Thiel's user avatar
Hannes Thiel's user avatar
Hannes Thiel
  • Member for 12 years, 5 months
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Weakenings of the Bounded Approximation Property
@YemonChoi Thank you. I agree that every reflexive space without AP shows that (3) does not imply the other (equivalent) properties.
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Weakenings of the Bounded Approximation Property
@BillJohnson Thank you. To summarize, $X$ has the BAP iff there is a uniformly bounded net of finite-rank operators $X^*\to X^*$ that converges to the identity on $X^*$ in point-weak*-topology. However, considering the same for the point-weak-topology is equivalent to the BAP for $X*$ (which implies the BAP for $X$, but not conversely.)
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$C^*$-algebra generated by those operators that are bounded on every $\ell_p$
I think the algebra $B_2$ contains every diagonal operator in $B(\ell_2)$ and also every permutation unitary. It would follow that $B_2$ also contains the uniform Roe algebra of every countable discrete group. Maybe it is known if uniform Roe algebras (of non-exact groups) contain $\prod_k M_k(\mathbb{C})$ ?
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Weakenings of the Bounded Approximation Property
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Weakenings of the Bounded Approximation Property
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Totally non hereditary $C^{*}$-subalgebras
What I read in Corollary 4 is: Assume that $A$ is a projectionless C*-algebra. Let $a$ and $b$ be two orthogonal positive elements. Then $\| \|a\|b- \|a\|b \| = \|a\|\cdot\|b\|$.
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Totally non hereditary $C^{*}$-subalgebras
Which generalization of Corollary 4 in the mentioned preprint do you mean?
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Koopman representation, weakly compact action, Ozawa Popa
What is the title of that article? According to zbMath, there are only three articles by Ozawa-Popa, and none in 2007.
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Do c.p.c. order zero maps between local C*-algebras map C*-subalgebras to C*-subalgebras?
Yes, a c.p.c. order-zero map $\varphi\colon A\to B$ between two C*-algebras corresponds to a *-homomorphism $\alpha\colon C_0((0,1])\otimes A \to B$ such that $\varphi(a)=\alpha(t\otimes a)$. Assume $B$ is $\sigma$-unital and $b$ is a strictly positive element in $B$. Given a set $F$ in $A$, consider $G=\{\alpha(t\otimes b)\}\cup \varphi(F)$. Then $\varphi(C^*(F))\subset \alpha(C_0((0,1])\otimes C^*(F)) = C^*(G)$.
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Do c.p.c. order zero maps between local C*-algebras map C*-subalgebras to C*-subalgebras?
Yes, this might seem counter-intuitive at first. But every element in $C(X)$ is contained in a finitely generated sub-C*-algebra of $C(X)$, and therefore $C(X)$ is the union (no closure needed) of all its finitely generated sub-C*-algebras.
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Ultraweak topology on B(X): Is the map X\otimes X* -> B(X)* isometric?
Thank you for the example. I thought (1) was easy to show, but I was too hasty. I find it very surprising that the map might not even be injective.
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Does the Approximation Property (AP) pass to quotients by amenable subgroups?
I mean the AP as in Definition 1.1 of Haagerup, Kraus (1994) # Approximation properties for group C-algebras and group von Neumann algebras [Trans. AMS 344]
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