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J Russell's user avatar
J Russell's user avatar
J Russell's user avatar
J Russell
  • Member for 12 years, 11 months
  • Last seen more than 1 year ago
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Alternating sum of square roots of binomial coefficients
Mark, yes, the positivity of this infinite set of finite sums feels to me quite similar to (and, as you point out, implies) the positivity of the infinite series I asked about earlier in the question you reference, and suffers from the same delicate cancellation of huge quantities. I sort of suspect that if you could crack the infinite series, you could crack this, too.
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Is $ \sum\limits_{n=0}^\infty x^n / \sqrt{n!} $ positive?
Gottfried, thank you for the numerical evaluation. This is consistent with how I believe the series behaves and with the numerical calculations I have done, although I didn't have the tools to push it out anywhere near as far as you did. A comment and an open-ended question: Presumably one could use interval arithmetic to produce a computer-aided proof of positivity for some negative values of $x$. Suppose you could prove positivity down to some large negative value. How large in magnitude would that $x$ have to be for you to really believe, absent a proof, that the series is positive?
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Is $ \sum\limits_{n=0}^\infty x^n / \sqrt{n!} $ positive?
@Gottfried: Thank you for pointing out the related math.stackexchange question (looking at $(n!)^\alpha$ for $\alpha \approx 2 > 1$. I did not realize that there was a connection to Bessel functions.
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Is $ \sum\limits_{n=0}^\infty x^n / \sqrt{n!} $ positive?
@Mark: Yes, I don't have any reason to believe that $\sqrt{n!}$ is any different than $(n!)^\alpha$, where $0 < \alpha < 1$ (although, hypothetically, $\alpha = {1 \over 2}$ might be an easier special case).
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Is $ \sum\limits_{n=0}^\infty x^n / \sqrt{n!} $ positive?
@Igor: I don't have any compelling evidence that this conjecture is true (although I believe it is). My best evidence is straightforward numerical experimentation. Also, intuition leads me to think it's true, and when I get stuck trying to prove it it's because "this intermediate step doesn't seem to help much," rather than "this intermediate step seems not to be true."
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