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Vidit Nanda's user avatar
Vidit Nanda's user avatar
Vidit Nanda's user avatar
Vidit Nanda
  • Member for 13 years, 2 months
  • Last seen more than 1 year ago
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When is the infimum of an arbitrary family of measurable functions also measurable?
Anton, of course that makes sense. Thank you. Yemon, I have made some changes that I hope will clarify matters somewhat. Bill: this sounds perfect for my needs. Could you please provide a reference?
revised
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angle between subspaces
John, what are $\lambda^p$ and $\Lambda^p$?
accepted
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Combinatorial analogues of curvature
Dear Liviu, thank you for this comprehensive answer, I will take a look at the references. Is the link to Fu's notes broken?
awarded
revised
Hopf reference sought
Removed misaligned "vec" arrows
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Incidences of rigorous proofs used in legal proceedings
Dear quid, thanks for your general advice. However, (1.) I was not belittling anyone either implicitly or otherwise, and (2.) as a general advice, there is only one 'e' in belittling.
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Incidences of rigorous proofs used in legal proceedings
I would love to see answers to this, but I fear that any minute now the army of "serious" users will try to close this question. I would like to pre-emptively request: please guys, can we leave this one alone?
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awarded
awarded
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is there a solution to this linear Diophantine system?
Igor: I don't think this works since the inverse of an integer matrix need not be an integer matrix. Can you elaborate on your solution?
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How fast can we *really* multiply matrices?
Igor: I was pointed to this paper by the reviewer: mrzv.org/publications/zzph-mmt/socg11 but I should warn you that I haven't yet had time to go through it and verify the claim
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Constructing a simplicial set homology-equivalent to a given CW complex
Dan, thanks. Regarding your projection map: you do have a homotopy equivalence because there is a homotopy version of the Vietoris-Begle theorem due to Smale (search: A Vietoris Mapping Theorem for homotopy). Essentially, if you require the fibers of your map to be contractible (instead of just acyclic), then you have a homotopy (instead of just homology) equivalence.
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