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bdx77
  • Member for 3 years, 10 months
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Inequality for Gaussian measures
Thank you very much!
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Inequality for Gaussian measures
This is very possible, but I simply do not see how.
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Comparison between $\|X\|_2$ and $\|X\|_{2,1}$
Thanks! I was hoping for a result of this kind without being able to prove it.
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How to demonstrate a correlation inequality?
I don't think we have Cov(XZ, Y) = E(D(1-D))V(Y) with my construction. The covariance is positive (and equal to $m_1$ V(Y)) but small enough to ensure the final inequality.
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How to demonstrate a correlation inequality?
Yes, sorry, I first misread your problem. I have completely modified my answer.
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How to demonstrate a correlation inequality?
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How to demonstrate a correlation inequality?
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Bound on the distribution of a ratio involving Gaussian distributions
Amazing! I very much doubt I would have found the answer by myself, even though I did look at Latala's paper on Royen's proof. So this was extremely useful :-) (Note: because I am new on this forum, my upvote does not appear yet)
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Bound on the distribution of a ratio involving Gaussian distributions
$I_K$ is indeed the identity matrix of dimension $K$ here.