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Martin's user avatar
Martin
  • Member for 3 years, 10 months
  • Last seen more than 3 years ago
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Rank of $A\otimes B - B\otimes A$
Thank you very much for the help.
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Rank of $A\otimes B - B\otimes A$
Thank you very much for the help.
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Rank of $A\otimes B - B\otimes A$
I now rephrased it to specify that A and B are random full-rank matrices.
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Rank of $A\otimes B - B\otimes A$
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Rank of $A\otimes B - B\otimes A$
Yes, of course; thanks for pointing it out. I hereby edited the post.
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Rank of $A\otimes B - B\otimes A$
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