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Quiet_waters
  • Member for 3 years, 11 months
  • Last seen more than 1 year ago
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Poisson Process x SIR model
Thank you so much for the explanation and references, I have for sure that a deeper study in these terms will help me a lot.
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Poisson Process x SIR model
@TobiasFritz thank you! I did not know about it. Searching the therm, this small work helped me to understand the idea: staff.math.su.se/daniel.ahlberg/notes-epidemics.pdf. Thank you so much.
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$\lim\inf_{t\to \infty} f(x(t))=0\Longrightarrow \lim\inf_{t\to\infty} \|x(t)\|=0$
Wow, that is a outstanding answer. Thank you very much.
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$\lim\inf_{t\to \infty} f(x(t))=0\Longrightarrow \lim\inf_{t\to\infty} \|x(t)\|=0$
@PierrePC But I am thinking... In this example $f$ has not a limit in infinit, because $\lim\inf_{x\to\infty} f=0$. Can be this $f$ a radially unbounded?
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$\lim\inf_{t\to \infty} f(x(t))=0\Longrightarrow \lim\inf_{t\to\infty} \|x(t)\|=0$
@PierrePC Wow, that is a really strange example, thank you for that, you are rigth
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$\lim\inf_{t\to \infty} f(x(t))=0\Longrightarrow \lim\inf_{t\to\infty} \|x(t)\|=0$
@PierrePC yes. Radially unbounded is a sufficient (but not necessary) condition, am I right? Thank you!
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$\lim\inf_{t\to \infty} f(x(t))=0\Longrightarrow \lim\inf_{t\to\infty} \|x(t)\|=0$
@PierrePC I was thinking. Positive definite continuous radially unbounded functions migth to fit the condition, am I right...?
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$\lim\inf_{t\to \infty} f(x(t))=0\Longrightarrow \lim\inf_{t\to\infty} \|x(t)\|=0$
I was thinking. Positive definite continuous radially unbounded functions migth to fit the condition, am I right...?
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$\lim\inf_{t\to \infty} f(x(t))=0\Longrightarrow \lim\inf_{t\to\infty} \|x(t)\|=0$
@PierrePC It seems to be right. The point is that I should use this $\lim\inf$ without more assumptions. But, this can be impossible. Thank you!
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$\lim\inf_{t\to \infty} f(x(t))=0\Longrightarrow \lim\inf_{t\to\infty} \|x(t)\|=0$
@PierrePC yes, it's solution of an ODE, but it's not related to $f$. Thank you
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$\lim\inf_{t\to \infty} f(x(t))=0\Longrightarrow \lim\inf_{t\to\infty} \|x(t)\|=0$
@MeisamSoleimaniMalekan Thank you! I have a doubt. $x(t)\not\in V\cap f^{-1}(V)$ ok. But if $x(t)\in f^{-1}(V)\setminus V$...? Is not possible?
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