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Ah, I forgot to specify that. Assume that it's the spectral norm (the 2-norm). However, the Frobenius norm is also fine since $\|A\|_2 \le \|A\|_F\le \sqrt{d} \|A\|_2$ when $d$ is the ambient dimension.
I think there is a misunderstanding. My question is on whether the error term of the 1st order Taylor expansion of $\exp_x$ can be realized as $(t^2/2) Q_x(w)$ for some appropriate $w \in T_x M$ with $\|w\| \le 1$. I don't think that this follows directly from Taylor's theorem? The best shot seems to be applying Taylor's theorem coordinate-wise to $t \mapsto \exp_x(tv)$ but that won't imply the desired result directly. Also, $J_x: T_x M \rightarrow \mathbb{R}^n$ is a required notation if we regard the tangent space as not a priori embedded in $\mathbb{R}^n$.
I think I have a resolution to the question asked, by applying Taylor's theorem coordinate-wise to the exponential map $t \mapsto \exp_x(tv)$ and bounding the error term crudely. This seems to yield that the error term is bounded by $Bt^2$ where $B = \frac n2 \sup_{w \in TM} \| \nabla_w w \| $ and $n$ is the ambient dimension. I'll clarify after I get some sleep.