Skip to main content
varkor's user avatar
varkor's user avatar
varkor's user avatar
varkor
  • Member for 4 years, 10 months
  • Last seen this week
revised
Coslices of $\mathbb D$-presentable categories
deleted 63 characters in body
Loading…
Loading…
comment
Being (co)cartesian as a property (rather than structure) of a plain monoidal category
Isn't it the case that a suitable property is "$\otimes$ has a right adjoint", per your answer to Monoidal categories whose tensor has a left adjoint? Or do you explicitly want a property in the form "every object is a monoid [...]"?
awarded
comment
Monoidal categories whose tensor has a left adjoint
@QiaochuYuan: thank you! This is a very good answer (along with the argument via Day convolution that was here previously). It's tricky to know which answer to accept, because the process of developing the proof was very much a collaboration: I wish I could accept both answers. I've decided to accept Tim's answer, simply because it contains the full proof that $\mathscr V$ has finite products, but I appreciate that this answer already contains many of the key ideas. Sorry, and thank you again!
awarded
comment
Monoidal categories whose tensor has a left adjoint
What a beautiful argument and elimination of the extra hypotheses! I wish I could accept both answers!
comment
Monoidal categories whose tensor has a left adjoint
Thanks, this is a very elegant argument. To check my understanding: if we require that the tensor and unit have left adjoints, then the unit will be terminal, and the argument demonstrating that $X \otimes Y \cong X \times Y$ carries through as written, establishing that finite products do exist in $\mathscr V$, without having to take it as an assumption, right? In this case, cartesian categories may be characterised as monoidal categories such that the tensor and unit are right adjoint. That the left adjoints are the diagonals follows automatically.
comment
Monoidal categories whose tensor has a left adjoint
@NoahSnyder: the concept is intended to be a weakening of the notion of cartesian category (where the cartesian product is right adjoint to the diagonal). However, one could just as well ask for a right adjoint instead, which would correspond to the cocartesian setting. I'm happy to know of references for either.
Loading…
comment
Multicategories vs Categories
Higher operads and multicategories are mentioned in Leinster's Higher Operads, Higher Categories, though the focus there is on defining higher categories using the machinery of operads.
comment
What are "nearly initial" objects really called?
From the paper: "(Our nomenclature draws on one of the basic examples of a Galois object: if $k \subset K$ is a Galois field extension, and $\mathscr A$ is the category of intermediate field extensions, then $K$ is Galois in $\mathscr A^{\text{op}}$.)"
answered
Loading…
answered
Loading…
comment
Distributive/CCC categories, exponentials
In a CCC, $(-) \times C$ is a left adjoint and thus preserves colimits (including coproducts).
comment
How does a theory give rise to a category with finite products?
@NoahSchweber: the morphisms of a Lawvere theory are entirely abstract. Lawvere is taking the morphisms $X \to 2$ to be predicates in a first-order logic, but their semantic intent is entirely opaque to the cartesian category. You could take the morphisms to be whatever you wanted.
comment
How does a theory give rise to a category with finite products?
@NoahSchweber: could you elaborate? It seems to me that the category $\mathbf C$ Lawvere is defining in the paper mentioned is a 2-sorted Lawvere theory (with the sorts being $A$ and $2$).
comment
How does a theory give rise to a category with finite products?
These are known as Lawvere theories. The book Algebraic theories is a good introduction (Chapter 11 specifically covers the concept Lawvere mentions here) and The Category Theoretic Understanding of Universal Algebra is a nice survey paper. Lawvere's thesis is not a particularly accessible starting point.
awarded
1
32 33
34
35 36
38