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Izar Urdin's user avatar
Izar Urdin's user avatar
Izar Urdin's user avatar
Izar Urdin
  • Member for 5 years, 3 months
  • Last seen more than a month ago
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How to find volunteer reviewers?
@ManfredWeis please send me in private your email ... I´m not an academic "eminence" but I can try to check it, and if I feel it is correct I´ll try to endorse you in arxiv.
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How to find volunteer reviewers?
@ManfredWeis have you finally found reviewers? I´m looking for reviewers too but it seems that they don't exist.
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Smooth approximation of a subharmonic function in the barrier sense
Are you looking for a functor wich transform a group (sequenced) of smooth functions to the same function? If you do then yes, we can find it. How ... I dono
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How can I improve my formal definitions?
I have created the chat room "Pioneers" ( chat.stackexchange.com/rooms/98162/pioneers ) to discuss this type of "innovations"; everyone is welcome;)
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What's the name of functions that produces a non deterministic solution without losing the exact solution?
Yep,I'm not sure if a Turing reduction don't lost the exact solution never. A function reduction as well as an approximation can lost the exact solution.
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How can I improve my formal definitions?
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Given a polynomial-time algorithm, can we compute an explicit polynomial time bound just from the program?
@JoelDavidHamkins I agree that the asnwer is yes, if and only if and only when, $e$ is polynomially computable. When not, you don't know, sometimes can be, and other will be linearly cost of $e$. I think the answer marked as correct can be improved denoting that. Note that the same algorithm for different inputs with the same length of entries ($n$) can compute sometimes a problem in P and sometines not, but if you know that for every input it is P, you can test in P your algorithm. However, I think you are asking for a boolean function; it is not the same as its implementation as a TM.
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How can I improve my formal definitions?
@NoahSchweber and company, all of you are very kind and I am very satisfied with your comments and advicing. I know the comments are not for this proposal, but I don't know how to thank you all this awsome response. Sincerely, thankyou very much.