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@Tyson. What I mean is: in partially Tait colored maps with faces of type F2, F3 or F4, if I have an impasse, Kempe chain color swapping may not work to solve an impasse, no matter how many swaps I try. Instead in maps without F2, F3 and F4, in all cases (not many: 40-50 cases) that I tryed, only by swapping colors I was able to solve the impasse. But this is just an hypothesis I'm verifying and is not related to the question. It is just the motivation of the question
@Tyson. Yes, by Fn (ex: F2, F3, F4) I mean faces bounded n edges. For the question, I don't want to count colorings in general (which I know it is hard), but starting from a specific configuration (the partially colored map in the picture) AND only proceding by Kempe chain color swaps (and non adding or removing colors from the map), how many different colorings can I have. I crossposted the question here because I had not received any answer (or hint) from math.stackexchange.com.
Thanks again. Plantri is really a great program and it is so fast. Where my program takes 1 minute to elaborate all graphs of 15 faces, Plantri is istantaneous.