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Sina
  • Member for 13 years, 8 months
  • Iran
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$Q(\sqrt{2})=Q((\sqrt{2}+1)^n)$
@Ali: Your answer is wrong. Consider $\alpha = \sqrt{2}+1$ in $Q(\sqrt{2})$
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$Q(\sqrt{2})=Q((\sqrt{2}+1)^n)$
Julian : I wanna find an $\alpha \in K$ such that $K=Q(\alpha)=Q(\alpha^2)=...$.
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Elementary Number Theory
@ Joel : Yes @ Franz : I can't understand the relation with ray class group !!!
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