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HNuer
  • Member for 13 years, 10 months
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Are all endomorphisms of C^* just power maps?
@Andreas, why is that? I've heard this before and I can easily prove the holomorphic case, but I can't think off the top of my head why the continuous result is true.
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Are all endomorphisms of C^* just power maps?
Fair enough. I didn't know what group structure you were using.
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Are all endomorphisms of C^* just power maps?
Although I think you mean $R_{>0}$, I see what you're saying, so thanks for the help!
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Zero and Negative Gromov-Witten invariants in genus 0
Two questions: 1) is your $K_{\mathbb P^2}$ Calabi-Yau? If you mean by the total space of the canonical bundle the scheme $Spec_{\mathbb P^2} Sym(\omgea_{\mathbb P^2})$ then I believe this has canonical bundle $\pi^*\mathcal O_{\mathbb P^2}(-6)$. So did you mean the total space of the line bundle which has sheaf of sections $\omega_{\mathbb P^2}$, which I agree would be Calabi-Yau. 2)Also, aren't the GV invariants conjectured to be nonnegative (for example see p. 19 of arxiv.org/abs/hep-th/9111025), so is that simply not believed anymore, or are they talking about different things?
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Singularities of Hilbert scheme of points on a surface
I don't know of a general statement for $S^{[2]}$, but I know that in the simple case of, say, a surface with one node, the singular locus of $S^{[2]}$ is known. I don't remember the details precisely, but I believe it looks locally like $S\times C$, where $C$ is the smooth plane conic $S$ induces (alternatively the exceptional divisor of the blow-up of $S$ at the node). Less geometrically, the singular locus as one might expect consists of length 2 subschemes which are support at least partially at the node. It would probably not be too hard to generalize this to any nodal surface.
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Number of irreducible and connected components constant in flat families
Not to be pedantic, but did you switch A) and B)? Also for your argument in B), $\dim H^0$ of the fiber being the number of connected components doesn't necessarily apply if the fibers have embedded components, which I believe normality rules out, so would reduced geometric fibers be enough there? Also I don't see how semicontinuity finishes it. It implies there is an open set of $S$ upon which the minimal number of components is achieved, but why does this imply it is all of $S$?
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Number of irreducible and connected components constant in flat families
You didn't want to put this in an answer and get the points? :) As usual Damian, your response has helped me a lot! Thanks
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