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I wanted to use an argument like this, but I’m worried that this apartment will not contain the whole ray $\rho$. Assuming $x$ and $y$ are in the a common chamber, can I always find an apartment containing $y$, $x$ and $\rho$?
X is locally compact and Polish. Actually, all these measures in my problem are area measures of (singular) Riemannian metrics on X. I wasn't completely sure that my assumptions guarantee convergence of the areas.
The definition of tightness I found is the following: a sequence $\mu_{n}$ is tight if for every $\epsilon>0$ there is a compact set $K$ such that $\mu_{n}(K^c)<\epsilon$ for all $n$. The difference with what I have is that for me this condition holds only for $n \geq n_{0}$ with $n_{0}$ depending on $\epsilon$.