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Đào Thanh Oai's user avatar
Đào Thanh Oai's user avatar
Đào Thanh Oai's user avatar
Đào Thanh Oai
  • Member for 6 years, 8 months
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Advanced view of the napkin ring problem?
@MichaelHardy Dear Sir, I know You four year ago on wiki, now this theorem have 9 cite publish in 5 Journals. Can You convert to en.wiki See also: mathoverflow.net/questions/234053/…
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Advanced view of the napkin ring problem?
@MichaelHardy Dear Sir, I know You four year ago on wiki, now this theorem have 9 cite publish in 5 Journals. Can You convert to en.wiki See also: mathoverflow.net/questions/234053/…
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Is every odd positive integer of the form $P_{n+m}-P_n-P_m$?
@GerhardPaseman When You ask, it is 1 AM in my country, I was going to sleep. So now the answer. Click link as follows to view. In the file, I define that. $Amn=P_{m+n}, Am=P_{m}, An=P_n, C=P_{m+n}-P_m-P_n$ the answer in this text file
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Is every odd positive integer of the form $P_{n+m}-P_n-P_m$?
I am sorry, I didn't print $m, n$ so please waiting me. @GerhardPaseman
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Is every odd positive integer of the form $P_{n+m}-P_n-P_m$?
I’m sorry, I think the result can checked by Computer
revised
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revised
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awarded
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Prove: If $P_n$ is $n$-$th$ prime number then $P_{n+m} \ge P_n+P_m$
My conjecture equivalent to $\pi(x+y) \le \pi(x)+\pi(y)+1$
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Prove: If $P_n$ is $n$-$th$ prime number then $P_{n+m} \ge P_n+P_m$
I am sorry. I think your proof maybe false at (2)==> (1). I think (2) ==> $\pi(x+y) \le \pi(x)+\pi(y)+1$ ?
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Prove: If $P_n$ is $n$-$th$ prime number then $P_{n+m} \ge P_n+P_m$
There is a good answer, if we can convert my conjecture with form $\pi(x+y) \le \pi(a)+\pi(b)$ where $a, b=f(x,y)$ after that we can compare with k-tuplet conjecture.
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awarded
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Prove: If $P_n$ is $n$-$th$ prime number then $P_{n+m} \ge P_n+P_m$
@GregMartin I am sorry, May You see answer below and my comment below?
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