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Obstruction to Bach flat metric
Self-dual and anti-self dual metrics (and hence locally conformally flat) are also Bach flat. So, for example, the product metric on $S^1 \times S^3$ is Bach flat, even though there is no Einstein metric on $S^1 \times S^3$.
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How to calculate the infimum of Yamabe functional on upper hemisphere
They are equivalent by stereographic projection when you choose a point on $\partial S_+^n$ to go to infinity.
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Closed manifolds of nonnegative curvature operator are symmetric spaces
Change isometric to diffeomorphic, because of the first two cases in the quoted theorem
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Closed manifolds of nonnegative curvature operator are symmetric spaces
The first case (with the irreducible assumption) is a manifold diffeomorphic to a sphere equipped with a metric whose curvature operator is nonnegative. These do not have to be locally symmetric (i.e. $\nabla R$ need not vanish).
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Closed manifolds of nonnegative curvature operator are symmetric spaces
Your conclusion should be diffeomorphic, not isometric, because of Igor's comment (small deformations of the standard metric on the sphere give metric with positive curvature operator which are not locally symmetric).
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Trace and divergence of the Bach tensor
Correct; the realization of the Bach tensor as the gradient only works in dimension four. As far as I can tell, the generalization of the Bach tensor to other dimensions is motivated by the Fefferman--Graham ambient metric.
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Proving an identity used in general relativity
I think it is better to call this (a variant of) the Bochner formula. The formula in the original post will (essentially) appear in any textbook under this name. "Reilly formula" usually refers to the result after integrating on a manifold with boundary and performing further algebraic manipulations on the boundary.
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Geometric interpretation of the Weyl tensor?
I have added some comments which give one possible interpretation. I recommend you read the introduction of Čap--Gover, cited in my answer, for further details or interpretations.