comment
Lee-Parker Yamabe problem proposition 4.6
@Marc You are right; I misread what they meant by $P$. The key point is anyway that $\psi$ isn’t zero at the south pole (as it would be for the bubbles you are worried about). I’ve modified accordingly, and hopefully not made any more mistakes guessing at their notation.
revised
Lee-Parker Yamabe problem proposition 4.6
added 1203 characters in body
Loading…
Loading…
awarded
awarded
comment
Definition of the conformal metric
Your explanation for the degeneracy of the metric is correct.
comment
Representation formula for solutions to fully nonlinear equations
The operator $u \mapsto \sigma_k(\lambda(A_{g_u}))$ is not linear, even after taking a power to make it homogeneous of degree $1$. For this reason, you do not have a linear representation formula.
answered
Loading…
comment
The linearization problem of fully nonlinear equation on standard sphere
For your second question: I computed the linearization $D_v\mathcal{F}_\mu(w)\rvert_{w=1}$. To do this, you just need to pick an arbitrary path $w_t$ with $w_0=1$ and $\dot w=v$. Mine is the straight line path with respect to your parameterization $g_w = w^{\frac{4}{n-2}}g$ of the conformal metric. For the first question, the point is that $\varphi_t$ is a conformal diffeomorphism. Its role is similar to the role of the Kelvin transform in the linked question.
comment
Kelvin transformation in fully nonlinear equation
In general you don’t have an equation which makes sense at $z=0$. There are some removable singularity theorems under appropriate assumptions on $u$ and $K$. You can probably find details in papers by Yanyan Li or Maria del Mar Gonzalez from the early- to mid-2000s, but I don’t know the most general reference.
comment
Kelvin transformation in fully nonlinear equation
Right, $g_0$ is the flat metric. Without knowing your background and interests, I'm unsure of what would be a "friendly" reference. A good starting point might be one of Alice Chang's survey articles on fully nonlinear elliptic equations.
Loading…
comment
The linearization problem of fully nonlinear equation on standard sphere
$v_i^j$ denotes the components of the matrix $g_0^{-1}D^2v$, where $D^2v$ is the Hessian of $v$ with respect to the metric $g_0$.
comment
The linearization problem of fully nonlinear equation on standard sphere
The tensor $g^{-1}A_g$ is a section of $T^\ast M \otimes TM \cong \mathrm{End}(TM)$, so for each point $p \in M$, the value of $g^{-1}A_g$ is a linear map, and hence one can meaningfully talk about the eigenvalues (or think of it as an $n \times n$ matrix). Without a metric, there is no way to talk about the eigenvalues of a section of $T^\ast M \otimes T^\ast M$. This is what I meant by needing to raise an index to define $\sigma_k$.
Loading…
Loading…
awarded
comment
Hodge decomposition for non-elliptic complexes
To go from an elliptic complex, as usually defined, to the Hodge decomposition theorem, you need to pick metrics on the vector bundles. If you only pick a pseudo-Riemannian metric, as in my first example, then you don’t get the decomposition. In my second and third examples, you do not (need to) pick a Riemannian metric to get the decomposition, but rather just a sub-Riemannian metric (the Levi form). Given your question about harmonic sections, it is better to think of an elliptic complex as requiring also the specification of a metric on each of the vector bundles.
Loading…