Skip to main content
Acccumulation's user avatar
Acccumulation's user avatar
Acccumulation's user avatar
Acccumulation
  • Member for 7 years
  • Last seen more than a month ago
comment
Is St. Petersburg a good place for the 2022 Int. Congress of Mathematicians
@JakubKonieczny "May I suggest that the feelings of Ukrainian mathematicians should be given a higher priority than the feelings of Russian mathematicians at a time like this?" Any Russian mathematician with any decency would object to it being held in Russian as well. So it's a question of whether the feelings of the Russian mathematicians who lack basic decency should take precendence.
comment
Is St. Petersburg a good place for the 2022 Int. Congress of Mathematicians
@user334725 "Even when countries are at war, there can be what might vaguely be called "cultural exceptions" to border controls." If the Russians had any respect for international norms, we wouldn't be in this situation in the first place.
comment
Is St. Petersburg a good place for the 2022 Int. Congress of Mathematicians
I don't think the issue for Ukrainian mathematicians is so much whether they'd be let in, so much as the Russians can be trusted to let them leave.
comment
Is there an "anti-choice axiom"?
"A admits a choice function is ∏A∖{∅} is non-empty." is -> if? And I have trouble seeing how an infinite set can be the union of two sets of strictly smaller cardinality.
comment
Loading…
comment
"The boat is not longer than it is."
Shouldn't it be "No, my yacht was not larger than it is"?
comment
Is it possible to create a polynomial $p(x)$ with this relation between $p(0)$ and $p(c)$?
It doesn't make sense to say that $n$ depends on neither $c$ nor $b$. If you were to word it as "Does there exist an $n$ such that for all $b,c$, there exist a polynomial of degree $n$ such that ..." Also, your first condition can almost be simplified to "the absolute value is strictly increasing".
comment
Are polynomials bounded on the primes possible?
It seems to me that there is a quantifier missing for $n$. Is it implied to be the universal one?
comment
Examples where "thin + thin = nice and thick"
You seem to be treat $A+B$ as being $\{a+b:a \in A,b \in B\}$. I think that deserves being made explicit.
comment
What's your favorite equation, formula, identity or inequality?
@BlueRaja What do you mean by that? Do you mean that his work, without this regularization, was insufficient for a scholarship?
comment
How many cones with angle theta can I pack into the unit sphere?
Seems to me that $\theta$ should be listed in the restrictions. You shouldn't rely on the title of the question for relaying crucial parts of the questions.
comment
Closed form expression for this infinite series?
You might want to put a carriage return after the equal sign to force all of the RHS to be on one line. And does "It's this expression for any real λ or x" mean "It's this expression if λ is real or x is real" rather than "It's this expression if λ is real and x is real"?
awarded
comment
Is There an Induction-Free Proof of the 'Be The Leader' Lemma?
@Joshua Did you produce a proof that if a proof that proof of X must exist must exist exists, then X must exist?
comment
Does the algorithm of the Greeks produce all prime numbers?
@PeterLeFanuLumsdaine $p_1=2$ is unnecessary only if one treats the null product as being 1.
comment
Does the algorithm of the Greeks produce all prime numbers?
Given that this algorithm is defined in terms of the set of prime numbers, it seems to me that there is little sense in which it "produces" the prime numbers.
comment
Does Zorn's Lemma imply a physical prediction?
Note also that given any measurement process, and any $t$, there exists an $\epsilon>0$ such if $10-\epsilon < x<10$, it will take more than $t$ seconds to determine that $x<10$.
Loading…
comment
If a triangle can be displaced without distortion, must the surface have constant curvature?
There is a slight ambiguity as to whether you are asking whether "$\exists T: T' \equiv T \rightarrow C$ is constant" or "$\forall T: T' \equiv T \rightarrow C$ is constant".