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Hugo Chapdelaine's user avatar
Hugo Chapdelaine's user avatar
Hugo Chapdelaine's user avatar
Hugo Chapdelaine
  • Member for 13 years, 11 months
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hyperbolic "Green function" on a product of upper half-planes
Dear Mateusz, yes I meant the continuous part of the spectrum of the Laplacian. I knew how to write down the heat kernel when the spectrum is discrete and I naively thought that for non-compact Riemannian manifolds one should also to take into account the continuous part (I imagined a kind of of integral over the continous part). In any case, thanks a lot for the reference. Using the explicit formula in (1.7) I shall try at least to recover the Green function, that will be a first test.
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hyperbolic "Green function" on a product of upper half-planes
The heat kernel $H(z,z',t)$ of $\mathfrak{h}$ has a continuous part since it is not compact. Using this approach do you at least recover $G_s(z,w)$ when you integrate $H$ with respect to $t$ from $0$ to $\infty$ ? In fact, because of the continuous part I'm not sure if this integral will converge...
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Show that $\sum_{i=0}^{\frac{p-1}{2}} {{\frac{p-1}{2}}\choose {i}}^2 x^{\frac{p-1}{2}-i}$ is separable
As Noam Elkies pointed out, this summation is probably equal modulo p to the solution $u(x)$ of a linear ODE of order 2: $S:y''+a(x)y'+b(x)y=0$ for suitable functions $a(x)$ and $b(x)$. If $u(x)$ had a double root, say at $x_0$, then $u(x_0)=0$ and $u'(x_0)=0$ would be a non-trivial solution to $S$ which contradicts the uniqueness of the solution. Of course, one has to make sure that the usual proof for the uniqueness goes through in charactersitic $p$, i.e., that there is no divsion by $p$.
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Finiteness theorems for profinite groups
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On the isometry group of a self cartesian product of a Riemannian space
Thanks Sebastian for bringing to my attention the so-called "de Rham decomposition" for a simply connected and complete Riemannian manifold. The key result which you are using may be found in the statement of Theorem III of de Rham's article entitled "Sur la reductibilite d'un espace de Riemann". Since I had in mind simply connected manifolds, this solves my question!
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