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Hugo Chapdelaine's user avatar
Hugo Chapdelaine's user avatar
Hugo Chapdelaine's user avatar
Hugo Chapdelaine
  • Member for 13 years, 11 months
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Characterizing the real analytic Eisenstein series
Well, by subtracting $\xi(2s)$ to $E(z,s)$ combined with some growth estimate "seems to be close" to saying that $\xi(2s)y^s$ is part of the constant term of the Fourier series $E(z,s)$. For example, if $s=3/4$ it says that $E(z,s)$ behaves asymptotically exactly like $\xi(3/2)\cdot y^{3/4}$.
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Characterizing the real analytic Eisenstein series
Dear Luis, this is a nice characterization. Of course specifying partly what the constant term of the Fourier series is, is not as much conceptual as what I was hoping at first, but may be one cannot do better than that.
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Characterizing the real analytic Eisenstein series
Do you have any precise idea on how to fix it?
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Characterizing the real analytic Eisenstein series
Thanks Matt, this is good observation! Probably, one should put some explicit restrictions on the constant $C(s)$ which appears implicitly in the big O notation of property (5).
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Characterizing the real analytic Eisenstein series
Dear Gunter Harder, I know what is wrong. In the formula appearing in the display if it is $\frac{\partial}{\partial s}E(z,s)$ and therefore this is why you pick up a $\log(y)$. So I think that what I wrote is correct.
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Characterizing the real analytic Eisenstein series
Dear Kunnysan, thanks for pointing out the inconsistancy with the functional equation and the shift with the constant!
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Characterizing the real analytic Eisenstein series
Dear GH, thanks for the comment you are perfectly. I'll add the Euler factor with the factor $1/2$ so that I at least get the right residues!
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A simple proof that parallelizable oriented closed manifolds are oriented boundaries?
Yes indeed, the anecdote behind your first answer is quite inspiring!
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A simple proof that parallelizable oriented closed manifolds are oriented boundaries?
Dear Andras, what do you mean by "take all the posets"?
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