14 votes
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Are (semi)simple Lie groups some sort of "homotopy quotient groups" of their maximal tori?

Here's the "answer" that I started writing, then put away for a while. The short answer is: although "T//W" is not the same as G, they "look sort of the same" from the point of view of certain ...
Charles Rezk's user avatar
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12 votes
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One element commutation classes of reduced decompositions of the longest element of the Weyl group

The reduced words that are in their own commutation classes are: $s = [123\cdots(n-2)(n-1)(n-2)\cdots321][23\cdots(n-3)(n-2)(n-3)\cdots32][3\cdots(n-4)(n-3)(n-4)\cdots3]\cdots$ the reversal of $s$ (...
Bridget Tenner's user avatar
11 votes
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Instructions for using Coxeter 3.0 software

If you type "help" immediately on entering the program, you'll get a fairly long and useful introductory message. At whatever level you are, you are supposed to be able to type "help," and then the ...
David Vogan's user avatar
10 votes
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What is known about finite dimensional modules over the nilCoxeter algebra?

This algebra has just one isomorphism class of simple module - let's call it $S$. Its projective cover is the regular representation, and is also the injective hull. The socle of the regular ...
Dave Benson's user avatar
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9 votes
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$N_{G}(E)/C_{G}(E)$ is the Weyl group of $G$?

$\newcommand{\ZZ}{{\mathcal Z}_G} \newcommand{\NN}{{\mathcal N}_G} \newcommand{\zz}{{\mathfrak z}_G} \newcommand{\Lie}{{\rm Lie\,}} \renewcommand{\tt}{{\mathfrak t}} \renewcommand{\gg}{{\mathfrak g}} \...
Mikhail Borovoi's user avatar
9 votes
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Invariants of cohomology of Springer sheaf

You want to look at the partial Grothendieck-Springer resolution, i.e. the variety of pairs $ (g \in G/ P_\mu, v \in g \mathfrak p_\mu g^{-1})$. The partial Grothendieck-Springer resolution is smooth, ...
Will Sawin's user avatar
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9 votes

One element commutation classes of reduced decompositions of the longest element of the Weyl group

I believe that for $n \geq 4$ there will be exactly $4$ such reduced words. One such word, call it $R_n$ can be constructed by starting with $s_{n-1}s_{n-2} \cdots s_2s_1s_2 \cdots s_{n-2}s_{n-1}$ and ...
Christian Gaetz's user avatar
8 votes
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When the longest element of Weyl group is rational?

Let $B$ be a Borel subgroup containing $T$. As $F(B)$ and $B$ are both Borel subgroups containing $T$ there exists an element $n \in N_G(T)$ such that ${}^nF(B) = B$. Thus the Frobenius endomorphism $...
Jay Taylor's user avatar
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8 votes
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Each $w\in W$ can be expressed as product of distinct reflections?

The answer is "yes" and there is a geometric explanation. Let $\mathcal{H}$ denote the set of hyperplanes corresponding to the reflections $s_\alpha$ with $\alpha\in\Phi^+$ (note that $s_\alpha=s_{-\...
Uriya First's user avatar
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7 votes
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Weyl group action on maximal tori

The first statement amounts to determining whether $T^w$ is connected. In the simplest case $G={\rm SL}_2$, $T$ may be identified with the multiplicative group ${\rm G}_m=\Bbb{C}^{\times}$, the Weyl ...
Victor Protsak's user avatar
7 votes

Cells in affine Weyl groups

You are asking a number of related questions here, most of which require more reading of Lusztig's papers. See the reference list in my conference paper here, for example. But note first that the ...
Jim Humphreys's user avatar
7 votes
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Fixed space of maximal torus and Weyl group

This paper of Humphreys addresses your second question (the first is answered in the comments - the $W$-module structure is independent of the choice of torus): https://people.math.umass.edu/~jeh/pub/...
Sam Gunningham's user avatar
7 votes

Number of reduced decompositions of the longest element of the Weyl group

Around the time Fomin and I wrote this paper, Tao Kai Lam applied the technique to type $D_n$. It emerged that it was "natural" to weight a reduced decomposition $\rho$ by $2^{d(\rho)}$, ...
Richard Stanley's user avatar
6 votes
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If a Weyl element preserves a root, then it has a representative which preserves the root space?

This is true if $G$ is split. First of all $w$ is represented by some $\tilde w\in N_G(T)\cap G(k)$ (see Borel-Tits, for example). Then $\text{Ad}\, \tilde w$ acts on $\mathfrak g_\alpha$ by some ...
Friedrich Knop's user avatar
6 votes
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On a criterion for rational-smoothness of Schubert varieties and an ambiguity of the taking the ambient Algebraic group to be simply connected or not

Expanded with lots of references at @JimHumphreys's request. Borel is Borel - Linear algebraic groups (2nd edition). Springer is Springer - Linear algebraic groups (2nd edition). Let $G$ be ...
LSpice's user avatar
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6 votes
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Parabolic subgroup of Weyl group

No. In $A_2$ with $I=\{s_1,s_2\}$, take $J=\{s_1\}$ and $u^J=id$ and $v^J=s_1s_2$. Then $M=W_J$ because $s_1\le s_1s_2$.
Nathan Reading's user avatar
6 votes
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What is the effect of tensoring with the sign representation on irreducible modules for a Type D Weyl group?

Recall the construction of such representations. Let $H\subset S_{2n}$ be the subgroup fixing the partition (so the two parts can be swapped) $$\{1,\dots,n\}\sqcup\{1',\dots,n'\}.$$ It is isomorphic ...
Kenta Suzuki's user avatar
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5 votes
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Characterization of all $w$ in the Weyl group satisfying $w \geq w_l w_{l, \theta}$

Yes, this follows from the fact that $x \mapsto w_l x$ is an antiautomorphism of the Bruhat order on a finite Coxeter group. (See Björner and Brenti, Proposition 2.3.4, for example, but their $w_0$ ...
Nathan Reading's user avatar
5 votes
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Parabolic Kazhdan-Lusztig polynomial coincide?

Yes, that's true. The standard recursive constructions will give you this fact easily, because the only group elements involved in $P_{x,w}^I$ are those which are $\leq w$ w.r.t. the Bruhat order. If $...
Johannes Hahn's user avatar
5 votes

Conjugacy of Regular Semisimple Subalgebras

It would help to recall Dynkin's definition of "regular semisimple subalgebra" of a complex semisimple Lie algebra (say $\mathfrak{g}$), which has not become standard in later literature. This just ...
Jim Humphreys's user avatar
5 votes
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Unicity of the BGG complex

Theorem 33 in the preprint [1] gives the uniqueness of BGG resolutions (= direct sums of Verma modules resolving a simple module) in category $\mathcal{O}$, both in regular and singular blocks. (...
Rafael Mrden's user avatar
  • 1,368
5 votes
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Number of reduced decompositions of the longest element of the Weyl group

This is easy to do in SageMath. E.g. the following code G = WeylGroup("F4") w = G.long_element_hardcoded() print(w) rw = w.reduced_words() len(rw) ...
Vít Tuček's user avatar
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5 votes
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Particular reduced expression of the longest element of Weyl group

Whenever $\ell(wv)=\ell(w)+\ell(v)$, you can construct a reduced word for $wv$ by producing one for $w$ and one for $v$ and then concatenating them. So, if you know an algorithm for producing reduced ...
Ben Webster's user avatar
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5 votes
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Describing characters of a reductive group in terms of characters of a maximal torus

I thought at first that you meant "trace character of a finite-dimensional, irreducible representation of $G$" by "character of $G$". Then this is false; for example, if $G$ is $\...
LSpice's user avatar
  • 11.4k
4 votes

Weyl group elements fixing a set of simple roots

I'm not sure whether there is an efficient way to answer your question (or a written reference), but it's possible to analyze the situation case-by-case. It's probably best to start with an ...
Jim Humphreys's user avatar
4 votes

Length of Weyl group element mapping highest root to a simple root

Ok I'm late on this, but I've just seen the question! Another way to look at it: the W-orbit of the highest root consists of the long roots, so the long roots are in bijection with the minimal coset ...
Daniel Juteau's user avatar
4 votes

Diagonal automorphisms for twisted Chevalley groups

First of all, I'd inquire what role the characteristic of the field plays here. It's true that the finite twisted groups rely on characteristics 2, 3 especiallu, but infinite twisted groups include ...
Jim Humphreys's user avatar
4 votes
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Weyl Group Element $w$ fixing a root, and its presentation as product of simple reflections $w=s_1\dots s_n$

This is definitely not true. For instance, already in $\Phi=B_2$, each root has a root orthogonal to it, so for every root there is some nontrivial element (in fact, a reflection) of the Weyl group ...
Sam Hopkins's user avatar
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4 votes

Each $w\in W$ can be expressed as product of distinct reflections?

After reading your comments, I come up with the following proof. I would like to know whether my proof is correct or not. For weyl group $W$, each $w\in W$ can be expressed as $w=s_{\beta_l}\cdots s_{...
James Cheung's user avatar
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4 votes
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Bruhat order and positive roots made negative

There is a counterexample in $\mathfrak{sl}_3$. Denote by $\alpha, \beta$ the simple roots, and $s,t$ the corresponding simple reflections. Then $\Phi_s^- = \{\alpha\}$ and $\Phi_{st}^- = \{\beta, \...
Rafael Mrden's user avatar
  • 1,368

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