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17 votes
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Is there a natural relationship between OEIS A127670 and Cayley's tree formula?

Yes there is a connection. While $n^{n-2}$ counts the number of vertex labeled trees on $n$ vertices, the expression $2^n(n+1)^{n-2}$ counts the number of edge labeled trees on $n$ edges. There is a ...
Gjergji Zaimi's user avatar
17 votes
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How does the number of trees on $n$ vertices *up to isomorphism* grow as $n \to \infty$?

For Q1 the answer is known to be $\sim C_1C_2^n n^{-5/2} $ for $C_1\approx 0.5349496061...$ and $C_2\approx 2.9955765856...$. This can be found in Flajolet and Sedgewick's "Analytic Combinatorics&...
Gjergji Zaimi's user avatar
16 votes

Groups acting on trees

Yes. You're assuming more than what's necessary. For an isometric group action on a Gromov-hyperbolic space, you have 5 possibilities (Gromov's classification): (a) bounded orbits (b) horocyclic (...
YCor's user avatar
  • 63.9k
15 votes
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History of deletion-contraction formula

This seems to have first been observed in Brooks, R.L.; Smith, C.A.B.; Stone, A.H.; Tutte, W.T., The dissection of rectangles into squares, Duke Math. J. 7, 312-340 (1940). ZBL0024.16501. See ...
Ian Agol's user avatar
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15 votes
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Göbel's correspondance between rooted trees and natural numbers

(I see this in the comments, too, but to ensure this has an actual answer...) Here are the first fifteen natural numbers after drawing an individual line segment (edge and node) beneath the root: As ...
Benjamin Dickman's user avatar
12 votes
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A combinatorial interpretation for $n$-ary trees for negative $n$

Here's an explanation of the combinatorial meaning of $T_{-n}(x)$. The combinatorial interpretation $T_n(x)$ is that it counts $n$-ary trees. More precisely, it counts ordered trees in which every ...
Ira Gessel's user avatar
12 votes
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Action of braid groups on regular trees

In the article A group theoretic criterion for property FA, Culler and Vogtmann notice that for $n \geq 5$, the braid group $B_n$ has property $A \mathbb{R}$, meaning that every non-trivial (i.e. ...
AGenevois's user avatar
  • 8,401
11 votes

A permutation problem

A simple brute-force of trees yields a counter-example with $n = 7$. Let $\{a_1, \ldots, a_7\} = [7]$, $T$ be a path of four vertices $v_1, v_2, v_3, v_4$, with $v_4$ adjacent to $v_5, v_6, v_7$. If ...
Mikhail Tikhomirov's user avatar
11 votes

Terminology about trees

They are also called trees. In that terminology, trees of your first kind are known as the well-founded trees, since they are trees where the tree order is well-founded (and well-founded linear ...
Joel David Hamkins's user avatar
10 votes
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Destroying Suslin, nothing special

Chapter IX of Proper and Improper Forcing addresses this issue. Shelah proves that Souslin's Hypothesis does not imply every Aronszajn tree is special, and he does this by investigating weak notions ...
Todd Eisworth's user avatar
10 votes

A tree with prime vertices

Not an answer, just a drawing of the tree including the OP's $2 \rightarrow 191$ path:          
Joseph O'Rourke's user avatar
10 votes
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Counting with trees

Let me complete Sam Hopkins' answer. The expression on the left is $$ \Psi\left(\sum_{i_1+\dots+i_{n+1}=n-1}{n-1\choose i_1,\dots,i_{n+1}}\prod_j x_j^{i_j+1}\right)\\ =\sum_{i_1+\dots+i_{n+1}=n-1}{...
Ilya Bogdanov's user avatar
9 votes

Almost graceful tree conjecture

I know no reference, but here is an easy way of achieving $|D|\geq\lceil n/2\rceil$ (for $n\geq 2$, surely). The vertices of every tree can be decomposed into stars (i.e., graphs of te form $K_{1,d}$ ...
Ilya Bogdanov's user avatar
9 votes

First inaccessible Suslin trees in L, an interesting detail

This will always be true. That is, I claim that forcing with a $\kappa$-Suslin tree always preserves all smaller cardinals, and indeed, preserves all cardinals and cofinalities. Theorem. Forcing with ...
Joel David Hamkins's user avatar
8 votes
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Spanning $k$-trees

Regarding the question 1a, Bern showed that checking existence of a spanning $k$-tree in a graph is NP-complete for any fixed $k \geq 2$ (also see another, more accessible relevant paper by Cai and ...
Mikhail Tikhomirov's user avatar
8 votes
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Growth rate of longest sequence of strings where no string is a subsequence of a later one

I suppose it's a good idea to turn my comment into an answer. The function $STR$ is basically the function $F$ defined by Friedman in this paper (more precisely, it's easy to show $STR(k)=F(k-1)+1$). ...
Wojowu's user avatar
  • 28.2k
8 votes

History of deletion-contraction formula

Not exactly a reference, but I found some discussion of this formula in Bill Tutte's graph-theoretic memoirs, Graph Theory as I Have Known it (Oxford, 1998). In Chapter 5 ("Algebra in Graph ...
Noam Zeilberger's user avatar
7 votes
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Chromatic number of square of a tree

The particular case of the square of a tree is easy to handle by producing a greedy $(\Delta+1)$-coloring starting from a root vertex and extending. However, much stronger results are known: The $k$-...
Gjergji Zaimi's user avatar
7 votes

Gromov hyperbolicity constant vs. Gromov-Hausdorff distance to a tree

Just to remove this question from the un-answered list. First of all, if $d_{GH}(X,Y)\le \epsilon$ then there is a $(1,2\epsilon)$-quasi-isometry $X\to Y$. See for instance Burago, D.; Burago, Yu.; ...
Moishe Kohan's user avatar
  • 12.2k
7 votes
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Are hyperbolic spaces actually better for embedding trees than Euclidean spaces?

I am not sure if the following paper answers your question. The abstract suggests so, but it is written in a computer science style that is less transparent to me in terms of stating a precise theorem....
user476736's user avatar
7 votes

A combinatorial interpretation for $n$-ary trees for negative $n$

Added Apr. 23, 2023: More interpretations of these sequences of numbers are provided in my blog post "Interpretations of the (−m)−Fuss-Narayana numbers for m>0". Added Apr. 10, 2023: (a ...
Tom Copeland's user avatar
  • 10.5k
7 votes
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Thick Canadian trees

$\newcommand{\Add}{\operatorname{Add}}$Start with a model $V$ satisfying $GCH$ (or just $2^{\omega}=\omega_1$ and $2^{\omega_1}=\omega_2$). Force over $V$ with the product $\Add(\omega,\omega_2)\times ...
Hannes Jakob's user avatar
  • 1,799
7 votes

Counting with trees

Here's a start. Your claim is equivalent to (and easier to understand as) $$ \sum_{T} \prod_{i=1}^{n+1} d_i(T)! = n! \, \frac{1}{2n+1}\binom{3n}{n}$$ where the sum is over all labeled trees $T$ on ...
Sam Hopkins's user avatar
  • 24.2k
7 votes
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Matrix-tree theorem for inverse matrices

There is a formula as a sum of forests, i.e., collections of trees, for arbitrary minors of any size and row/column selection, for arbitrary matrices. So it can be applied for the numerator and the ...
Abdelmalek Abdesselam's user avatar
6 votes
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Counting some binary trees with lots of extra stucture

I was able to find an interesting generalization of your formula, but I'm having trouble finding a reference in the literature. Let's call a 0-1-2 tree, a rooted tree where every vertex can have no ...
Gjergji Zaimi's user avatar
6 votes
Accepted

Number of independent sets of a random tree

The exact average number of independent sets in a random labelled tree of $n$ vertices is $$ E_n = \sum_{k=0}^{n-1} \binom{n}{k} n^{1-k} (n-k)^{k-1}. $$ To prove this, use the Matrix Tree Theorem (or ...
Brendan McKay's user avatar
6 votes
Accepted

Bijective proof of formula for rooted binary forests

I think the following might do the trick: Erdös, Péter L., A new bijection on rooted forests, Discrete Math. 111, No.1-3, 179-188 (1993). ZBL0785.05049.
Martin Rubey's user avatar
  • 5,792
6 votes

Asymptotics of unrooted labeled forests

The idea in the book by Flajolet-Sedgewick is to use singularity analysis. The generating function $F(z)=\exp(U(z))$ with $U=T-T^2/2$ inherits the dominant singularity $e^{-1}$ of $T(z)=-W(-z)$, where ...
Bruno Salvy's user avatar
6 votes
Accepted

Quotient graph of a tree

Yes, if $G$ is connected (and non-empty for simplicity). Choose a vertex $v\in V(G)$. We define a tree $T$ in which the vertices are all the paths in $G$ that start in $v$ (including the path of ...
M. Winter's user avatar
  • 13.6k
6 votes
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Tree property at weak inaccessibles

In his paper Boolean extensions which efface the Mahlo property William Boos proves the following consistency result: Theorem. Assume GCH holds and $\kappa$ is weakly compact. Then there exists a ...
Mohammad Golshani's user avatar

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