4
votes
Accepted
Does $U_q (\mathfrak{sl}_2)$ have a universal $R$-matrix?
$U_q(\mathfrak{sl}_2)$ is indeed not quasitriangular with the usual $R$-matrix. Instead it satisfies a weaker condition of being braided [1].
One can certainly show that the usual universal R-matrix ...
4
votes
Is there an "arithmetic cobordism category"?
Unfortunately, I think we're still quite far away from knowing the answer to your question. Fortunately, a lot of progress has been made without answering your question.
The key advance here was ...
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