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Orthosymplectic superalgebra

It is still $\bigwedge^2(V)$, but you have to compute that in the super sense: $$\bigwedge\nolimits^2(V_0 \oplus V_1) = \bigwedge\nolimits^2(V_0) \oplus (V_0\otimes V_1) \oplus \operatorname{Sym}^2(...
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