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3 votes

Eigenvectors of $P^\top P$ for 0/1 matrices $P$

I believe that this is false. We don't need to make use of $N \gg m$; indeed, square $m \times m$ matrices will suffice. A 0/1 matrix can have singular values that are exponentially small in their ...
Eric Neyman's user avatar
1 vote

Some but not all eigenvectors mutually orthogonal

I encountered this situation when I was studying a weird kind of radiative corrections in my formal analyses of relativistic quantum field theories with weak violations of Lorentz symmetry (arXiv ...
Buzz's user avatar
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