4 votes

Simple proof that exactness implies strong mixing

I think the martingale theory really captures exactly what's happening. I don't know any other proof, but suspect that you would end up reproducing the backwards martingale theorem in some form? I am ...
Anthony Quas's user avatar
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4 votes

Simple proof that exactness implies strong mixing

Not sure if this is what you're looking for, and I'm not an expert on exact systems, but: your definition of exact implies that $\bigcap_{n \geq 0} T^{-n} \mathcal{B} = \mathcal{N}$, where $\mathcal{B}...
Ronnie Pavlov's user avatar

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